Often in your work you need to communicate with others through screenshots in the model? After posting a place, having trouble finding the element in model? Thanks to my extension to PyRevit -> PyLab you can generate the Id of elements in the model as well as those linked!
In article about program for “revit linked element id”:
The program was created to improve communication on various models. Unfortunately, currently in Revit it is possible to check the Id of elements located only in the opened model, while the overlays allow you to receive the Id of only linked objects. This type of division makes it difficult to communicate via e-mails, for example. The user must then generate the Id separately. Thanks to the “Ids” function, everything is in one place! If you don’t have the overlay yet, I encourage you to download it. You can find the full instructions in my post PYLAB – free revit addin.
The program in order allows you to select elements contained in the model, and then elements located in linked Revit models. Then, after selecting the elements, the program returns the following information:
Thanks to this information, finding the discussed elements in individual models is easy and does not require the use of several commands. In addition, information about the family and type facilitates orientation, even when discussing collisions.
Below is the program code from the first version of the addin. For more please visit my GitHub, where new versions of the overlay will appear on a regular basis.
from rpw import revit
from Autodesk.Revit.UI.Selection import *
from pyrevit import forms
doc = revit.doc
uidoc = revit.uidoc
def Pargetstr(element, name):
return (element.GetParameters(name))[0].AsValueString()
## Pick model elements
try:
with forms.WarningBar(title="Pick elements in model"):
collector = uidoc.Selection.PickObjects(ObjectType.Element)
except Exception as e:
pass
# print(e)
## Pick linked elements
try:
with forms.WarningBar(title="Pick elements in linked model"):
collector_link = uidoc.Selection.PickObjects(ObjectType.LinkedElement)
except Exception as e:
pass
# print(e)
## Print Ids
try:
for i in collector:
print("====")
print("Model element "+str(i.ElementId))
el=doc.GetElement(i.ElementId)
print((Pargetstr(el, "Family and Type")))
except:
print("No picked elements")
try:
for i in collector_link:
print("====")
el=doc.GetElement(i.ElementId)
linkdoc=el.GetLinkDocument()
el=linkdoc.GetElement(i.LinkedElementId)
print("Linked element "+str(i.ElementId))
print((Pargetstr(el, "Family and Type")))
except Exception as e:
# print(e)
print("No picked linked elements")Please report any irregularities in the operation of the program that occur during use on my social accounts or GitHub.
